h=0.1;                                      % grid size
x=0:h:2;                                    % specify the partition of the interval [0,2]
clear y;                                    % clear possibly existing variable y
y(1)=1;                                     % initial condition: x1=0, thus y(1) corresponds to y(x1)=1
f=inline('3*exp(-4*x)-2*y');                % define your function
size(x);                                    % size of x to be used in determining the size of vector i
for i=1:20 y(i+1)=y(i)+h*f(x(i),y(i));end   % compute the approximation
Y_exact=2.5*exp(-2*x)-1.5*exp(-4*x);        % the exact solution
error = abs(Y_exact-y)'                     % the difference between exact
                                            %  and approximate solutions
plot(x,y,'--',x,Y_exact)                    % plot of the exact and approximate (dashed curve) solutions                                            %
error =

         0
    0.0587
    0.0793
    0.0794
    0.0696
    0.0560
    0.0418
    0.0289
    0.0180
    0.0092
    0.0025
    0.0024
    0.0058
    0.0080
    0.0093
    0.0099
    0.0100
    0.0097
    0.0092
    0.0086
    0.0079